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CBSE Class 12 Math 2024 All Sets Solved Paper

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Question : 7 of 20
Marks: +1, -0
The differential equation dydx=F(x,y)\frac{dy}{dx} = F(x, y) will not be a homogeneous differential equation, if F(x, y) is
Solution:  
The differential equation dydx=F(x,y)\frac{dy}{dx} = F(x, y) is homogenous differential equation if F(λx,λy)=F(x,y)F(\lambda x, \lambda y) = F(x, y).
Examining the above options, (B), (C) and (D) are homogeneous differential equation as below.
(B) F(λx,λy)=λyλx=yx=F(x,y)F(\lambda x, \lambda y) = \frac{\lambda y}{\lambda x} = \frac{y}{x} = F(x, y)
(C) F(λx,λy)=(λx)2+(λy2)λxλy=λ2x2+λ2y2λ2xy=x2+y2xy=F(x,y)F(\lambda x, \lambda y) = \frac{(\lambda x)^2 + (\lambda y^2)}{\lambda x \lambda y} = \frac{\lambda^2 x^2 + \lambda^2 y^2}{\lambda^2 x y} = \frac{x^2 + y^2}{x y} = F(x, y)
(D) F(λx,λy)=cos2(λyλx)=cos2(yx)=F(x,y)F(\lambda x, \lambda y) = \cos^2\left(\frac{\lambda y}{\lambda x}\right) = \cos^2\left(\frac{y}{x}\right) = F(x, y)
Now we examine (A) as below:
(A) F(λx,λy)=cosλxsin(λyλx)=cosλxsin(yx)F(x,y)F(\lambda x, \lambda y) = \cos \lambda x - \sin\left(\frac{\lambda y}{\lambda x}\right) = \cos \lambda x - \sin\left(\frac{y}{x}\right) \neq F(x, y), so (A) is not a homogeneous differential equation.
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