We have $f : Z \rightarrow Z$ defined by $f(x)=3x-5$Let us check if the function is injectiveAssume, $f(x_1) = f(x_2) \forall x_1, x_2 \in Z$$\Rightarrow 3x_1-5=3x_2-5$$\Rightarrow 3x_1=3x_2$$\Rightarrow x_1=x_2$Thus, f is injectiveNow, let us check if the function is surjective.For f to be surjective, for every $y \in Z,$ there must exist on $x \in Z$ such that $f(x)=y$y = 3x - 5$\Rightarrow x = \frac{y+5}{3}$If y = 1, then $x = \frac{1+5}{3}=2,$ which is an integer.If y = 2, then $x = \frac{2+5}{3}=\frac{7}{2},$ which is not an integer.Since, x is not always an integer for every integer y, f is not surjective.f is not bijective because it is not surjective.The reason is correct, as a bijective function must be injective and surjective.