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CBSE Class 12 Math 2026 All Sets Solved Paper

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Question : 14 of 20
Marks: +1, -0
The value of m for which the points with position vectors ij+2k,2i+mj+5k and 3i+11j+6k are collinear, is
Solution:  
Let the three points be A, B & C
Their position vectors are
OA=2i+mj+5k
OB=3i+11j+6k
OC=ij+2k
AB=OBOA=(32)i+(11m)j+(65)k
=i+(11m)j+k
BC=OCOB=4i12j4k
Now,14=11m12=14
11m12=14
11m=3
m=113
m=8
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