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CBSE Class 12 Math 2026 All Sets Solved Paper

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Question : 4 of 20
Marks: +1, -0
If Δ1=∣100020003∣\Delta_{1}=\begin{vmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 3 \end{vmatrix} and Δ2=∣020100006∣\Delta_{2}=\begin{vmatrix} 0 & 2 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 6 \end{vmatrix}, then
Solution:  
Δ1=∣100020003∣=1(6)=6\Delta_{1}=\begin{vmatrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 3 \end{vmatrix}=1(6)=6
Δ2=∣020100006∣=−2(6)=−12\Delta_{2}=\begin{vmatrix} 0 & 2 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 6 \end{vmatrix}=-2(6)=-12
Δ2=−2Δ1\Delta_{2}=-2 \Delta_{1}
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