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CBSE Class 12 Math 2026 All Sets Solved Paper

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Question : 7 of 20
Marks: +1, -0
The least value of f(x)=x312x,x[0,3] is
Solution:  
f(x)=x312x,x[0,3]
f(x)=3x212=0
x2=123x=±2
f(0)=0,f(3)=9,f(2)=16
Least value of f(x) is -16 at x = 2.
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