CBSE Class 12 Math 2026 All Sets Solved Paper

Question : 9 of 20

Marks: +1, -0

The value of

∫↙{-1}↖{1} \;{x^{3}}/{x^{2}+2 | x | +1} \dx

Solution:

I=∫↙{-1}↖{1} \;{x^{3}}/{x^{2}+2 | x | +1} \dx

.....(i)
Then, by using the property

∫↙{a}↖{b} f(x) \dx=∫↙{a}↖{b} f(a+b-x) \dx

I=∫↙{-1}↖{1} \;{-x^{3}}/{x^{2}+2 | x | +1} \dx

.......(ii)
adding (i) & (ii)
2I = 0

⇒ I=0

Go to Question:

Prev Question

Next Question