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CBSE Class 12 Physics 2014 Delhi Set 2 Paper

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Question : 3 of 8
Marks: +1, -0
An electric dipole of length 2‌cm, when placed with its axis making an angle of 60∘ with a uniform electric field, experiences a torque of 8√3‌Nm. Calculate the potential energy of the dipole, if it has a charge of ±4‌nC.
Solution:  
τ‌=pEsin‌θ
8√3‌=pEsin‌θ
pE‌
√3
2
‌=8√3
So, pE=16
Potential energy of the dipole
‌=−pE‌cos‌θ
U‌=−pE‌cos‌60
U‌=−16×0.5
U‌=−8J
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