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CBSE Class 12 Physics 2014 Outside Delhi Set 1 Paper

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Question : 14 of 30
Marks: +1, -0
Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 1.0×107m21.0 \times 10^{-7} \mathrm{m}^2 carrying a current of 1.5A1.5 \mathrm{A}. Assume the density of conduction electrons to be 9×10289 \times 10^{28} m3\mathrm{m}^{-3}.
Solution:  
vd=InAq  , where  v_d = \frac{I}{n A q} \; \text{, where} \;
I is the current
nn is charge density
qq is the charge of electron and
AA is the cross sectional area
  vd=  1.59×1028×1.0×107×1.6×1019\; v_d = \; \frac{1.5}{9 \times 10^{28} \times 1.0 \times 10^{-7} \times 1.6 \times 10^{-19}}
  vd=10.4×104m/sec\; v_d = 10.4 \times 10^{-4} \mathrm{m} / \mathrm{sec}
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