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CBSE Class 12 Physics 2014 Outside Delhi Set 3 Paper

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Question : 5 of 9
Marks: +1, -0
Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 2.5×107 m22.5 \times 10^{-7} \text{ m}^2 carrying a current of 2.7 A2.7 \text{ A}. Assume the density of conduction electrons to be 9×10289 \times 10^{28} m3\text{m}^{-3}.
Solution:  
We know that drift velocity, vd=InAqv_d=\frac{I}{n A q}
Where II is the current, nn is charge density, qq is charge of electron and A is cross-sectional area.
vd=279×1028×2.5×107×1.6×1019v_d=\frac{27}{9 \times 10^{28} \times 2.5 \times 10^{-7} \times 1.6 \times 10^{-19}}
vd=7.5×104 m/sv_d=7.5 \times 10^{-4} \text{ m/s}
or vd=0.75 mm s1v_d=0.75 \text{ mm s}^{-1}
This is the required average drift velocity.
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