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CBSE Class 12 Physics 2015 Delhi Set 1 Paper

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Question : 18 of 26
Marks: +1, -0
State the principle of working of a galvanometer. A galvanometer of resistance GG is converted into a voltmeter to measure upto VV volts by connecting a resistance R1R_1 in series with the coil. If a resistance R2R_2 is connected in series withit, then it can measure upto   V2\;\frac{V}{2} volts. Find the resistance, in terms of R1R_1 and R2R_2 required to be connected to convert it into a voltmeter that can read upto 2V2V . Also find the resistance GG of the galvanometer in terms of R1R_1 andR2R_2.
Solution:  
Working Principle
Finding the required resistance
Finding the resistance GG of the Galvanometer
Working Principle: A current carrying coil experiences a torque when placed in a magnetic field which tends to rotate the coil and produces an angular deflection.
V  =Ig(G+R1)V\;=I_g (G+R_1)
  V2  =Ig(G+R2)\;\frac{V}{2}\;=I_g (G+R_2)
⇒    2  =  G+R1G+R2\Rightarrow \;\; 2\;=\;\frac{G+R_1}{G+R_2}
⇒    G=R1−2R2\Rightarrow \;\; G=R_1-2 R_2
Let R3R_3 be the resistance required for conversion into voltmeter of range 2V2V
∴  2V  =Ig(G+R3)\therefore \;2 V\;=I_g (G+R_3)
     Also     V  =Ig(G+R1)\;\;\text{ Also }\;\;V\;=I_g (G+R_1)
∴  2  =  G+R3G+R1\therefore \;2\;=\;\frac{G+R_3}{G+R_1}
∴  R3  =G+2R1\therefore \;R_3\;=G+2 R_1
  =R1−2R2+2R1\;=R_1-2R_2+2 R_1
  =3R1−2R2\;=3 R_1-2 R_2
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