CBSE Class 12 Physics 2016 Delhi Set 1 Paper

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Question : 15
Total: 26
Two parallel plate capacitors X and Y have the same area of plates and same separation between them. X has air between the plates while Y contains a dielectric medium of εr=4.

(i) Calculate capacitance of each capacitor if equivalent capacitance of the combination is 4µF.
(ii) Calculate the potential difference between the plates of X and Y.
(iii) Estimate the ratio of electrostatic energy stored in X and Y.
Solution:  
(i) Calculation of capacitance of each capacitor
(ii) Calculation of potential difference
(iii) Estimation of ratio of electrostatic energy
(i) Let CX=C
Cγ=4C (as it has a dielectric medium of εγ =4 )
For series combination of two capacitors
‌
1
C
‌
=‌
1
CX
+‌
1
CY

⇒‌‌‌
1
4µF
‌
=‌
1
C
+‌
1
4C

‌
1
4µF
‌
=‌
5
4C

⇒‌‌C‌=5µF
‌ Hence ‌‌‌CX‌=5µF
CY‌=20µF
Hence CX=5µF
Cγ=20µF
‌‌ (ii) Total charge ‌Q=CV
‌=4µF×15V=60µC
‌VX=‌
Q
CX
=‌
60µC
5µF
=12V

‌VY=‌
Q
CY
=‌
60µC
20µF
=3V

‌‌ (iii) ‌‌
Ex
Ey
=‌
‌
Q2
2CX
Q2
2CY
=‌
CY
CX
=‌
20
5
=4
:1
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