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CBSE Class 12 Physics 2016 Outside Delhi Set 1 Paper

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Question : 12 of 26
Marks: +1, -0
(i) State law of Malus.
(ii) Draw a graph showing the variation of intensity (I)(I) of polarised light transmitted by an analyser with angle (heta)( heta) between polariser and analyser.
(iii) What is the value of refractive index of a medium of polarising angle 6060^{\circ} ?
Solution:  
Statement
Plotting the graph
Calculating value of (μ)(\mu) refractive index
(i) When the pass axis of a polaroid makes an angle hetaheta with the plane of polarisation of polarised light of intensity I0I_0 incident on it, then the intensity of the transmitted emergent light is given by I=I0I=I_0 cos2heta\cos^2 heta
Note : If the student writes the formula I=I0cos2hetaI=I_0 \cos^2 heta and draws the diagram give 1 mark
(ii)
(iii)   μ=taniβ\; \mu = \tan i_{\beta}
  =an60=3=1.7\; = an 60^{\circ} = \sqrt{3} = 1.7
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