Test Index

CBSE Class 12 Physics 2019 Delhi Set 1 Paper

© examsnet.com
Question : 12 of 27
Marks: +1, -0
Plot a graph showing variation of de Broglie wavelength (λ)(\lambda) associated with a charged particle of mass mm, versus 1V\frac{1}{\sqrt{V}}, where VV is the potential difference through which the particle is accelerated. How does this graph give us the information regarding the magnitude of the charge of the particles?
Solution:  
Plot of the graph showing the variation of λ\lambda Vs 1V\frac{1}{\sqrt{V}}
Information regarding magnitude of charge
λ=h2mqV\because \lambda = \frac{h}{\sqrt{2 m q V}}
λ1V=h2mq=slope\frac{\lambda}{\frac{1}{\sqrt{V}}} = \frac{h}{\sqrt{2 m q}} = \text{slope}
q=h22m(slope)2q = \frac{h^2}{2 m (\text{slope})^2}
© examsnet.com
Go to Question: