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CBSE Class 12 Physics 2019 Delhi Set 1 Paper

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Question : 6 of 27
Marks: +1, -0
SECTION -B

Two bulbs are rated (P1,V) and (P2,V). If they are connected (i) in series and (ii) in parallel across a supply V, find the power dissipated in the two combinations in terms of P1 and P2.
Solution:  
Calculation of Power dissipation in two combinations
R1‌=‌
V2
P1
,R2=‌
V2
P2
,
Ps‌=‌
V2
Rs
=‌
P1P2
P1+P2

‌
1
Ps
‌=‌
1
P1
+‌
1
P2

‌
1
Rp
‌=‌
1
R1
+‌
1
R2
=‌
P1+P2
V2

∴Pp‌=‌
V2
Rp
=P1+P2
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