CBSE Class 12 Physics 2019 Delhi Set 3 Paper

Question : 3 of 8

Marks: +1, -0

SECTION - B

Obtain the expression for the ratio of the de Broglie wavelengths associated with the electron orbiting in the second and third excited states of hydrogen atom.

Solution:

2πr=nλ
For second excited state (n=3)
r=0.529(n)2Å
=0.529(3)2
⇒2π(0.529)(3)2=3λ2
For third excited state n=4
r=0.529(4)2
⇒2π(0.529)(4)2=4λ3
⇒‌

3λ2

4λ3

=‌

(3)2

(4)2

‌

λ2

λ3

=3:4

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