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CBSE Class 12 Physics 2019 Delhi Set 3 Paper

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Question : 7 of 8
Marks: +1, -0
Two infinitely long straight wires A1A_1 and A2A_2 carrying currents II and 2I2 I flowing in the same direction are kept ' dd ' distance apart. Where should a third straight wire A3A_3 carrying current 1.5I1.5 I be placed between A1A_1 and A2A_2 so that it experiences no net force due to A1A_1 and A2A_2 ? Does the net force acting on A3A_3 depend on the current flowing through it?
Solution:  
Finding the position of third wire
Reason
    F1  =  μ04π  I×1.5Ix\Rightarrow \;\; F_1\;=\;\frac{\mu_0}{4 \pi} \;\frac{I \times 1.5 I}{x}
F2  =  μ04π  2I×1.5I(dx)F_2\;=\;\frac{\mu_0}{4 \pi} \;\frac{2 I \times 1.5 I}{(d-x)}
For no force on the conductor A3A_3
μ04π  I×1.5Ix  =  μ04π  2I×1.5I(dx)\frac{\mu_0}{4 \pi} \;\frac{I \times 1.5 I}{x}\;=\;\frac{\mu_0}{4 \pi} \;\frac{2 I \times 1.5 I}{(d-x)}
1x  =  2(dx)\frac{1}{x}\;=\;\frac{2}{(d-x)}
3x  =d3 x\;=d
x  =  d3x\;=\;\frac{d}{3}
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