CBSE Class 12 Physics 2019 Outside Delhi Set 1 Paper

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Question : 7
Total: 27
A photon and a proton have the same de-Broglie wavelength λ . Prove that the energy of the photon is (2mλc∕h) times the kinetic energy of the proton.
Solution:  
For writing expression for energy of photon
For writing expression for kinetic energy of proton
For proving the relationship between the two
Energy of photon, Ep=‌
hc
λ

For proton, ‌λ=‌
h
mv

‌mv=‌
h
λ

Kinetic energy of proton,
‌Ek=‌
1
2
m
v2

‌Ek=‌
1
2
‌
h2
mλ2

‌Ep=(‌
2mλc
h
)
Ek
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