A heavy nucleus P of mass number 240 and ...

CBSE Class 12 Physics 2020 Delhi Set 1 Paper

Question : 24 of 37

Marks: +1, -0

A heavy nucleus

P

of mass number 240 and binding energy

7.6 \text{MeV}

per nucleon splits in to two nuclei

Q

and

R

of mass numbers 110 and 130 and binding energy per nucleon

8.5 \text{MeV}

and 8.4

\text{MeV}

, respectively. Calculate the energy released in the fission.

Solution:

Total BE of

P=240 \times 7.6=1824 \text{MeV}

\text{BE}

Q=110 \times 8.5=935 \text{MeV}

B E

R=130 \times 8.4=1092 \text{MeV}

Total BE of

Q

and

R=(935+1092)=2027 \text{MeV}

Total energy released in the fission

\;=2027-1824

\;=203 \text{MeV}

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