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CBSE Class 12 Physics 2020 Delhi Set 1 Paper

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Question : 26 of 37
Marks: +1, -0
Use Bohr's model of hydrogen atom to obtain the relationship between the angular momentum and the magnetic moment of revolving electron.
Solution:  
In Bohr model of Hydrogen atom, electron is modeled as a point negative charge rotating in a circular orbit about a fixed axis about a nucleus.
Magnetic moment MLM_{L}
Let us consider
r=r= radius of the orbit
v=v= velocity
e=e= charge of electron
m=m= mass of electron
Time period (T)= circumference  velocity =2πrv(T)=\frac{\text{ circumference }}{\text{ velocity }}=\frac{2\pi r}{v}
Current(i) =−eT=−e2πrv=−ev2πr=\frac{-e}{T}=\frac{-e}{\frac{2\pi r}{v}}=\frac{-e v}{2\pi r}
The magnetic moment due to a current loop enclosing an area AA is given by:
ML=iA=−ev2πr×A=−ev2πr×πr2M_{L}=iA=\frac{-e v}{2\pi r}\times A=\frac{-e v}{2\pi r}\times \pi r^{2} =−erv2=−merv2m=\frac{-e r v}{2}=\frac{-m e r v}{2m}
L=L= Angular momentum =mvr=mvr
So, ML=−e2mLM_{L}=\frac{-e}{2m}L
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