When a conducting loop of resistance 10 and ...

CBSE Class 12 Physics 2020 Delhi Set 1 Paper

Question : 34 of 37

Marks: +1, -0

When a conducting loop of resistance

10 \Omega

and area

10 \text{ cm}^2

is removed from external magnetic field acting normally, the variation of induced curren in the loop with time is as shown in the figure -

Find the -

(a) total charges passed through the loop.

(b) change in magnetic flux through the loop.

Solution:

Given,

\text{Area}=A=10\text{ cm}^2=\frac{10}{10000}\text{ m}^2

Resistance

=R=10 \Omega

From the graph, change in current

=0.4\text{ A}

Change in time

=1.0\text{ s}

(i) Total charge passed through the loop

=\text{current}\times\text{time}=0.4\times1.0

=0.4\text{ C}

(ii)

\lvert e\rvert=\frac{\Delta\phi}{\Delta t}

Or,

iR=\frac{\Delta\phi}{\Delta t}

Or,

0.4\times10=\frac{\Delta\phi}{1.0}

\therefore

Change in flux

=\Delta\phi=4\text{ Wb}

(iii)

\lvert e\rvert = A \frac{\Delta B}{\Delta t}

\text{Or, } iR = A \frac{\Delta B}{\Delta t}

\text{Or, } 0.4\times10 = \frac{10}{10000} \frac{\Delta B}{1.0}

\therefore \Delta B = 4000 \text{ T}

Go to Question:

Prev Question

Next Question