An electric dipole of length 2 cm is placed at an angle of ...

CBSE Class 12 Physics 2023 All Sets Paper

Question : 1 of 18

Marks: +1, -0

An electric dipole of length 2 cm is placed at an angle of

30^∘

with an electric field

2× 10^5

N/C. If the dipole experiences a torque of

8× 10^{-3}

Nm. the magnitude of either charge of the dipole, is

Solution:

Given

τ = 8× 10^{-3}Nm

l = 2 cm

θ = 30^∘

E =

2× 10^5 N\/C

Then

τ=PE sin θ

p = ql

τ = qle sin θ

8× 10^{-3} = q× 2× 10^{-2}× 2× 10^5× sin30^∘

8× 10^{-3} = q× 4× 10^3× \;{1}/{2}

q=\;{8× 10^{-3}}/{2× 10^3}

q = 4µ C

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