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CBSE Class 12 Physics 2023 All Sets Paper

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Question : 10 of 18
Marks: +1, -0
The diagram shows four energy level of an electron in Bohr model for hydrogen atom. Identify the transition in which the emitted photon will have the highest energy.
Solution:  
In transition I
E3−E1=  −13.6n32+  13.6n12E_3-E_1=\;\frac{-13.6}{n_3^2}+\;\frac{13.6}{n_1^2}
=  −13.69+  13.61=\;\frac{-13.6}{9}+\;\frac{13.6}{1}
=1.51+13.6=1.51 + 13.6
E3−E1=12.09  evE_3-E_1=12.09\;\text{ev}
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