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CBSE Class 12 Physics 2023 All Sets Paper

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Question : 17 of 18
Marks: +1, -0
Assertion (A): The equivalent resistance between points A and B in the given network is 2R.
Reason (R): All the resistors are connected in parallel
Solution:  
1R1=12+12        1R2=12+12\frac{1}{R_1} = \frac{1}{2} + \frac{1}{2} \;\;\;\; \frac{1}{R_2} = \frac{1}{2} + \frac{1}{2}
1R=22        1R2=22\frac{1}{R} = \frac{2}{2} \;\;\;\; \frac{1}{R_2} = \frac{2}{2}
1R=11        1R2=1\frac{1}{R} = \frac{1}{1} \;\;\;\; \frac{1}{R_2} = 1
R1=1ΩR_1 = 1\Omega        R2=1Ω\;\;\;\; R_2 = 1\Omega
Then
R=R1+R2R = R_1 + R_2
R=1+1R = 1 + 1
R = 2Ω
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