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CBSE Class 12 Physics 2023 Delhi Set 1 Paper

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Question : 4 of 35
Marks: +1, -0
A square shaped coil of side 10 cm10\ \text{cm}, having 100 turns is placed perpendicular to a magnetic field which is increasing at 1 T/s1\ \text{T}/\text{s}. The induced emf in the coil is
Solution:     👈: Video Solution
N  =100N\;=100
A  =  110×110 m2A\;=\;\frac{1}{10} \times \frac{1}{10}\ \text{m}^2
dBdt  =1.0 Ts−1\frac{dB}{dt}\;=1.0\ \text{Ts}^{-1}
emf  =NA  dBdt\text{emf}\;= NA\; \frac{dB}{dt}
∴ emf  =100×110×110×1\text{emf}\;=100 \times \frac{1}{10} \times \frac{1}{10} \times 1
  =1 V\;=1\ \text{V}
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