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CBSE Class 12 Physics 2023 Delhi Set 1 Paper

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Question : 7 of 35
Marks: +1, -0
The energy of a photon of wavelength λ\lambda is
Energy of photon,
  E=hv\; E = h v
But   v=  cλ\; v = \; \frac{c}{\lambda}
So, E=  hcλE = \; \frac{h c}{\lambda}
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