Figure shows a plot of stopping potential ( ...

CBSE Class 12 Physics 2023 Delhi Set 2 Paper

Question : 3 of 11

Marks: +1, -0

Figure shows a plot of stopping potential

( V_0)

versus

\;\frac{1}{\lambda}

, is the wavelength of the radiation causing photoelectric emission from a surface. The slope of the line is equal to

Solution: 👈: Video Solution

From Einstein's equation,

e V_0\;= hv - h v_0

or,

V_0\;=\;\frac{hv}{e}-\;\frac{h v_0}{e} \;\; \left[ \because v=\;\frac{h}{c}\right]

or,

V_0\;=\;\frac{hc}{\lambda e}-\;\frac{hc}{\lambda_0 e}

So, the slope of

V_0

vs.

\frac{1}{\lambda}

graph is

\frac{hc}{e}

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