A point object in air is placed symmetrically at a distance of 60 {\cm} in front of a concave spherical surface of refractive index 1.5 . If the radius of curvature of the surface is 20 {\cm}, find the position of the image formed.

CBSE Class 12 Physics 2023 Outside Delhi Set 2 Paper

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Question : 10

Total: 13

A point object in air is placed symmetrically at a distance of 60‌cm in front of a concave spherical surface of refractive index 1.5 . If the radius of curvature of the surface is 20‌cm, find the position of the image formed.

Solution: 👈: Video Solution

For refraction from concave spherical surface,
‌

µ2

v

−‌

µ1

u

‌=‌

µ2−µ1

R

‌ or, ‌‌‌

1.5

v

−‌

1

(−60)

‌=‌

1.5−1

−20

‌ or, ‌‌‌

1.5

v

+‌

1

60

‌=−‌

0.5

20

‌ or, ‌‌‌

1.5

v

+‌

1

60

‌=−‌

1

40

‌‌ or, ‌‌‌

1.5

v

‌=−‌

1

40

−‌

1

60

‌∴‌v‌=−36‌cm
Image in formed in the medium where the object lies at a distance 36‌cm from point P.

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