CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

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Question : 1
Total: 13
SECTION - A

The energy of a photon of wavelength 663‌nm is
E‌=‌
hc
λ

‌=‌
6.6×10−34×3×108
663×10−9

‌=2.98×10−19J
‌‌≈3.0×10−19J
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