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CBSE Class 12 Physics 2023 Outside Delhi Set 3 Paper

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Question : 4 of 13
Marks: +1, -0
The radius of 1327X{}_{13}^{27}X nucleus is RR. The radius of 53125Y{}_{53}^{125}Y nucleus will be
R=R0A1/3R = R_0 A^{1/3}
 For X, R=R0(27)1/3\text{ For X, } R = R_0 (27)^{1/3}
 Or, R=3R0\text{ Or, } R = 3 R_0
R0=R3\therefore R_0 = \frac{R}{3}
 For Y, R=R0(125)1/3\text{ For Y, } R' = R_0 (125)^{1/3}
 Or, R=5R0\text{ Or, } R' = 5 R_0
R=5R3\therefore R' = \frac{5R}{3}
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