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CBSE Class 12 Physics 2024 All Sets Solved Paper

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Question : 7 of 14
Marks: +1, -0
The momentum (in SI units) associated with a photon of energy 1.5 eV is:
Solution:  
The momentum p associated with a photon can be calculated using the equation:
p=Ecp = \frac{E}{c}
where E is the energy of the photon and c is the speed of light in a vacuum.
Given that the energy E of the photon is 1.5 eV, and the speed of light c is approximately 3×1083 \times 10^8 meters per second, we can calculate the momentum p:
p=1.5 eVcp = \frac{1.5\ \mathrm{eV}}{c}
p1.5×1.6×1019J3×108 m/sp \approx \frac{ \frac{1.5 \times 1.6 \times 10^{-19}}{\mathrm{J}} }{3 \times 10^8\ \mathrm{m/s}}
p2.4×1019J3×108 m/sp \approx \frac{ \frac{2.4 \times 10^{-19}}{\mathrm{J}} }{3 \times 10^8\ \mathrm{m/s}}
p8×1028 kg m/sp \approx 8 \times 10^{-28}\ \mathrm{kg\ m/s}
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