For a hydrogen atom, this expression simplifies to $E_n = -\;\frac{13.6}{n^2}$ eV. From this relation, we observe that:$E_n \propto \;\frac{1}{n^2}$As n increases, the energy becomes less negative (i.e., increases) and approaches zero as n → ∞.The energy is proportional to $\;\frac{1}{n^2}$