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CBSE Class 12 Physics 2026 All Sets Paper

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Question : 16 of 16
Marks: +1, -0
Assertion (A): In Young’s double-slit experiment, the fringe width for dark and bright fringes is the same.
Reason (R): Fringe width is given by β=λDd\beta = \frac{\lambda D}{d}, where symbols have their usual meanings.
Solution:  
The fringe width (β) is defined as the distance between two consecutive bright fringes:
β=yn+1yn=(n+1)λDdnλDd=λDd\beta = y_{n+1} - y_n = \frac{(n+1)\lambda D}{d} - \frac{n\lambda D}{d} = \frac{\lambda D}{d}
Similarly, the distance between two consecutive dark fringes:
β=yn+1yn=(2n+1)λD2d(2n1)λD2d=λDd\beta = y'_{n+1} - y'_n = \frac{(2n+1)\lambda D}{2d} - \frac{(2n-1)\lambda D}{2d} = \frac{\lambda D}{d}
Since both expressions give the same value, the fringe widths for bright and dark fringes are equal.
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