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CBSE Class 12 Physics 2026 All Sets Paper

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Question : 2 of 16
Marks: +1, -0
The momentum of a photon associated with a microwave of wavelength 4.00 cm is:
Solution:  
First, convert the wavelength into SI units: λ = 4.00 cm = 0.04 m. Now compute the momentum:
p=  6.63×10340.04p = \;\frac{6.63 \times 10^{-34}}{0.04}
p=1.6575×1032kgms1p = 1.6575 \times 10^{-32}\,\text{kg}\,\text{ms}^{-1}
Rounding to appropriate significant figures gives 1.66×1032kgms11.66 \times 10^{-32}\,\text{kg}\,\text{ms}^{-1}
The momentum of the photon is 1.66×1032kgms11.66 \times 10^{-32}\,\text{kg}\,\text{ms}^{-1}.
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