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ICSE Class 10 Chemistry 2015 Paper

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Consider the following reaction and based on the reaction answer the questions that follow :
(NH4)2Cr2O7→heatN2(g)+4H2O(g)+Cr2O3(\mathrm{NH}_4)_2\mathrm{Cr}_2\mathrm{O}_7 \xrightarrow{\text{heat}} \mathrm{N}_2(g)+4\mathrm{H}_2\mathrm{O}(g)+\mathrm{Cr}_2\mathrm{O}_3
Calculate:
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Question : 63 of 85
Marks: +1, -0
the mass of grams of Cr2O3\mathrm{Cr}_2\mathrm{O}_3 formed at the same time.
Solution:  
If 252 gm252\,\mathrm{gm} of (NH4)2Cr2O7(\mathrm{NH}_4)_2\mathrm{Cr}_2\mathrm{O}_7 produces 152 gm152\,\mathrm{gm} of Cr2O3\mathrm{Cr}_2\mathrm{O}_3 .
Then 63 gm63\,\mathrm{gm} of (NH4)2Cr2O7(\mathrm{NH}_4)_2\mathrm{Cr}_2\mathrm{O}_7 produces =152252×63=38 gm=\frac{152}{252}\times 63 = 38\,\mathrm{gm} .
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