Test Index

ICSE Class 10 Chemistry 2018 Paper

Show Para  Hide Para 
Aluminum carbide reacts with water according to the following equation :
Al4C3+12H2O→4Al(OH)3+3CH4\mathrm{Al}_4 \mathrm{C}_3 + 12 \mathrm{H}_2 \mathrm{O} \rightarrow 4 \mathrm{Al}(\mathrm{OH})_3 + 3 \mathrm{CH}_4
[Relative molecular weight of Al4C3=144\mathrm{Al}_4 \mathrm{C}_3 = 144; Al(OH)3=78]\mathrm{Al}(\mathrm{OH})_3 = 78]
© examsnet.com
Question : 57 of 80
Marks: +1, -0
What volume of methane at s.t.p. is obtained from 12 g12\,\mathrm{g} of aluminum carbide?
Solution:  
Al4C3+12H2O→  4Al(OH3)+3CH4144gm4×78gm3×22.4\begin{array}{lllllll} \mathrm{Al}_4\mathrm{C}_3 & + & 12\mathrm{H}_2\mathrm{O} & \rightarrow & \;4\mathrm{Al}(\mathrm{OH}_3) & + & 3\mathrm{CH}_4 \\ 144\mathrm{gm} & & & & 4\times 78\mathrm{gm} & & 3\times 22.4 \end{array}
If 144 gm144\,\mathrm{gm} of Al4C3\mathrm{Al}_4\mathrm{C}_3 releases 3×22.4 l3\times 22.4\,\mathrm{l} of CH4\mathrm{CH}_4 at STP
then 12 gm12\,\mathrm{gm} of Al4C3\mathrm{Al}_4\mathrm{C}_3 releases   3×22.4144×12\;\frac{3\times 22.4}{144} \times 12
=5.6 l=5.6\,\mathrm{l}
© examsnet.com
Go to Question:
Prev Question
Next Question