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ICSE Class 10 Chemistry 2020 Paper

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Question : 70 of 86
Marks: +1, -0
Calculate the number of moles present in 160gm160 \mathrm{gm} of NaOH\mathrm{NaOH}.
[Atomic Mass : Na=23,H=1,O=16\mathrm{Na}=23, \mathrm{H}=1, \mathrm{O}=16 ]
Solution:  
Molecular mass NaOH\mathrm{NaOH}
  =23+16+1=40\;=23+16+1=40
  No. of moles    =    wt. in gm    GMM  \; \text{No. of moles} \; \; = \; \frac{ \; \text{wt. in gm} \; }{ \; \text{GMM} \; }
  =  16040=4\; = \; \frac{160}{40}=4
  =4  moles.  \; =4 \; \text{moles.} \;
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