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ICSE Class 10 Chemistry 2023 Paper

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The following sketch illustrates the process of conversion of Alumina to Aluminum :
Study the diagram and answer the following :
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Question : 20 of 88
Marks: +1, -0
Write the reactions taking place at the electrodes ' YY ' (anodes) and ' ZZ ' (cathode) respectively.
Solution:  
At anode ( Y)Y) - at anode carbon is oxidised to carbonmonoxide then carbon dioxide.
2C+O2→2CO2\mathrm{C} + \mathrm{O}_2 \rightarrow 2\mathrm{CO}
2CO+O2→2CO22\mathrm{CO} + \mathrm{O}_2 \rightarrow 2\mathrm{CO}_2
6O2−−12e−→6[O]6\mathrm{O}^{2-} - 12\mathrm{e}^{-} \rightarrow 6[\mathrm{O}]
3O+3O→3O23\mathrm{O} + 3\mathrm{O} \rightarrow 3\mathrm{O}_2
At cathode (Z)−(Z)-
4Al3+  (molten)  +12e−→4Al(l)4\mathrm{Al}^{3+} \; \text{(molten)} \; +12\mathrm{e}^{-} \rightarrow 4\mathrm{Al}(l)
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