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ICSE Class 10 Chemistry 2023 Paper

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Question : 63 of 88
Marks: +1, -0
The Empirical formula of an organic compound is CHCl2\mathrm{CHCl}_2.
If its relative molecular mass is 168 , what is its molecular formula?
[At. Wt. C=12, H=1, Cl=35.5\mathrm{C}=12,\ \mathrm{H}=1,\ \mathrm{Cl}=35.5 ]
Solution:  
Empirical formula of organic compound =CHCl2= \mathrm{CHCl}_2
Mass of CHCl2\mathrm{CHCl}_2
  =12+1+35.5×2\; = 12+1+35.5 \times 2
  =84 amu.\; = 84 \text{ amu}.
Relative molecular mass =168=168
Molecular formula == ?
Multiplication factor (n)(n)
  =  Relative molecular massEmpirical formula mass\; = \; \frac{\text{Relative molecular mass}}{\text{Empirical formula mass}}
  =  16884=2\; = \; \frac{168}{84} = 2
Molecular formula   =(Empirical formula)n\; = (\text{Empirical formula})_n
  =(CHCl2)2=C2H2Cl4\; = ( \mathrm{CHCl}_2 )_2 = \mathrm{C}_2 \mathrm{H}_2 \mathrm{Cl}_4
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