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ICSE Class 10 Physics 2013 Paper

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Question : 28 of 70
Marks: +1, -0
How much heat energy is released when 5 g5\ \mathrm{g} of water at 20∘ C20^{\circ}\ \mathrm{C} changes to ice at 0∘ C0^{\circ}\ \mathrm{C} ?
[Specific heat capacity of water =4.2 Jg−10=4.2\ \mathrm{Jg}^{-10} C−1C^{-1}.
Specific latent heat of fusion of ice =336 J=336\ \mathrm{J} g−1]g^{-1}]
Solution:  
 Heat energy     =mcΔT+mL\text{ Heat energy }\;\;=m c \Delta T+m L
    =5×4.2×(20−0)+5×336\;\;=5 \times 4.2 \times (20-0)+5 \times 336
    =420+1680\;\;=420+1680
    =2100   Joule.   \;\;=2100 \;\text{ Joule. }\;
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