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ICSE Class 10 Physics 2013 Paper

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Question : 31 of 70
Marks: +1, -0
A radioactive nucleus undergoes a series of decays according to the sequence
XβX1αX2αX3  ". "  X \xrightarrow[\beta]{} X_1 \xrightarrow[\alpha]{} X_2 \xrightarrow[\alpha]{} X_3 \; \text{". "}\;
If the mass number and atomic number of X3X_3 are 172 and 69 respectively, what is the mass number and atomic number of XX ?
Solution:  
ZAXβZ+1AX1αZ+12A4X2{}^{A}_{Z}X \overset{\beta}{\rightarrow} {}^{A}_{Z+1}X_1 \overset{\alpha}{\rightarrow} {}^{A-4}_{Z+1-2}X_2 αZ3A8X3\overset{\alpha}{\rightarrow} {}^{A-8}_{Z-3}X_3
Given : Atomic number of X3=69X_3=69 and mass number of X3=172X_3=172 i.e. 69172X3{}^{172}_{69}X_3
72X180β73X1180α71X2176α69X3172{}_{72}X^{180} \overset{\beta}{\rightarrow} {}_{73}X_1^{180} \overset{\alpha}{\rightarrow} {}_{71}X_2^{176} \xrightarrow[\alpha]{} {}_{69}X_3^{172}
Mass number of X=180X=180
Atomic number of X=72X=72
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