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ICSE Class 10 Physics 2014 Paper

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Question : 40 of 66
Marks: +1, -0
The lens mentioned in 6(b) above is of focal length 25 cm25\,\text{cm}. Calculate the power of the lens.
Solution:  
Given : f=25 cm=0.25 mf=25\,\text{cm}=0.25\,\text{m}
Power of lens (in D)
=1Focal length (in metre)=\frac{1}{\text{Focal length (in metre)}}
=10.25=10025=4 D.=\frac{1}{0. 25}=\frac{100}{25}=4\,\text{D}.
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