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ICSE Class 10 Physics 2016 Paper

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A battery of emf 12 V12\ \mathrm{V} and internal resistance 2 Ω2\ \Omega is connected with two resistors AA and BB of resistance 4 Ω4\ \Omega and 6 Ω6\ \Omega respectively joined in series.
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Question : 64 of 73
Marks: +1, -0
Electrical energy spent per minute in 4Ω4 \Omega Resistor.
Solution:  
Energy spent=I2Rt\text{Energy spent} = I^2 R t
=(1)2×4×60= (1)^2 \times 4 \times 60
=240J= 240 \,\text{J}
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