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ICSE Class 10 Physics 2017 Paper

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Question : 13 of 65
Marks: +1, -0
The human ear can defect continuous sounds in the frequency range from 20Hz20\\ \mathrm{Hz} to 20,000 Hz\mathrm{Hz}. Assuming that the speed of sound in air is 330ms−1330\\ \mathrm{ms}^{-1} for all frequencies, calculate the wavelengths corresponding to the given extreme frequencies of the audible range.
Solution:  
Given : Frequency range =20Hz=20\\ \mathrm{Hz} to 20,000 Hz\mathrm{Hz}, speed of sound in air(v)=330ms−1\mathrm{air}( v)=330\\ \mathrm{ms}^{-1}.
We Know,
v;=fλ.v\\;=f \lambda .
∴ Case ;1→330;=20×λ1\therefore\\ \text{ Case }\\; 1 \rightarrow330\\;=20 \times \lambda_1
λ1;=;33020=16.5m\lambda_1\\;=\\;\frac{330}{20}=16.5\\ \mathrm{m}
 Case ;2→330;=20,000×λ2\text{ Case }\\; 2 \rightarrow330\\;=20,000 \times \lambda_2
λ2;=;33020,000=0.0165m.\lambda_2\\;=\\;\frac{330}{20,000}=0.0165\\ \mathrm{m}.
∴\therefore Wavelength range is 0.0165m0.0165\\ \mathrm{m} to 1.65m1.65\\ \mathrm{m}.
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