ICSE Class 10 Physics 2017 Paper

A pulley system with $V R=4$ is used to lift a load of $175\,\text{kgf}$ through a vertical height of $15\,\text{m}$ . The effort required is $50\,\text{kgf}$ in the downward direction. $(g=10\,\text{N}\,\text{kg}^{-1})$
Calculate:

Question : 30 of 65

Marks: +1, -0

M.A. of the pulley system.

Solution:

\;\text{ M.A. }\;=\;\frac{\;\text{ Load }\;}{\;\text{ Effort }\;}=\;\frac{175\ \text{kgf}}{50\ \text{kgf}}=3.5

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