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ICSE Class 10 Physics 2017 Paper

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Question : 51 of 65
Marks: +1, -0
A certain sound has a frequency of 256 hertz and a wavelength of 1.3m1.3 \text{m} .
1. Calculate the speed with which this sound travels.
2. What difference would be felt by a listener between the above sound and another sound travelling at the same speed, but of wavelength 2.6m2.6 \text{m} ?
Solution:  
Given : f=256Hz,λ=1.3mf=256 \text{Hz}, \lambda=1.3 \text{m}
(1) We know,
V  =fλV\; = f \lambda
  =256×1.3\;=256 \times 1.3
  =332.8ms−1\;=332.8 \mathrm{ms}^{-1}
(2) Given: λ′=2.6m,f′=\lambda' = 2.6 \text{m}, f' = ?
∵    f′=Vλ′=332.82.6\because\;\; f' = \frac{V}{\lambda'} = \frac{332.8}{2.6}
  =128Hz\;=128 \text{Hz}
Since, the frequency of sound decreases, so it will appear to the listener having less pitch (or strillness) as compared to the previous sound.
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