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ICSE Class 10 Physics 2022 Paper

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Question : 15 of 45
Marks: +1, -0
Calculate the thermal capacity of 40 g40\ \mathrm{g} of water.
[Specific heat capacity of water =4200=4200  Jkg−1∘C−1 ]\ \mathrm{Jkg}^{-1}{}^{\circ}\mathrm{C}^{-1}\ ]
Solution:  
Given : m=40 g=401000=0.04 kgm=40\ \mathrm{g}=\frac{40}{1000}=0.04\ \mathrm{kg}
C=4200 J kg−1 ∘C−1C=4200\,\mathrm{J\,kg^{-1}\,{}^{\circ}C^{-1}}
Thermal capacity (C′)(C')
  =mass(m)×   Specific heat capacity   (C)\;=\text{mass}(m)\times\;\text{ Specific heat capacity }\;(C)
  =0.04×4200\;=0.04\times 4200
  =168 J∘C−1\;=168\ \mathrm{J}^{\circ}\mathrm{C}^{-1}
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