Find the ratio of the area of ABC : area of ...

ICSE Class X Math 2013 Paper

In the given figure, $A B$ and $D E$ are perpendicular to $B C$ .

Question : 15 of 46

Marks: +1, -0

Find the ratio of the area of

\triangle ABC

: area of

\triangle DEC

Solution:

\;\;\frac{\;\text{ Area of }\;\triangle ABC}{\;\text{ Area of }\;\triangle DEC}=\;\frac{AB^2}{DE^2}

\;( \because \triangle ABC \sim \triangle DEC)

\;=\;\frac{(6)^2}{(4)^2}=\;\frac{36}{16}=\;\frac{9}{4} \;\text{ or }\; 9:4

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