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ICSE Class X Math 2013 Paper

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In the given figure,
∠BAD=65∘,∠ABD=70∘,∠BDC=45∘\angle BAD = 65^{\circ}, \angle ABD = 70^{\circ}, \angle BDC = 45^{\circ}
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Question : 9 of 46
Marks: +1, -0
Find ∠ACB\angle ACB.
Solution:  
∠ACB=∠ADB\angle ACB = \angle ADB
(Angles in the same segment of a circle)
∴    ∠ACB=45∘    (∵∠ADB=45∘)\therefore \;\; \angle ACB = 45^{\circ} \;\; (\because \angle ADB = 45^{\circ})
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