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ICSE Class X Math 2014 Paper

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In the figure, ∠DBC=58∘.BD\angle D B C = 58^{\circ} . B D is a diameter of the circle. Calculate:
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Question : 15 of 52
Marks: +1, -0
∠BAC\angle BAC
Solution:  
∠BAC=∠BDC\angle BAC = \angle BDC
(Angle of same segment are equal)
∠BAC=32∘\angle BAC = 32^{\circ}
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