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ICSE Class X Math 2014 Paper

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In the figure given below, diameter ABA B and CDC D of a circle meet at PP . PT is a tangent to the circle at T.CD=7.8cm,PD=5cm,PDT . C D=7.8 \text{cm}, P D=5 \text{cm}, P D =4cm=4 \text{cm} . Find :
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Question : 36 of 52
Marks: +1, -0
the length of tangent PT.
Solution:  
From eq. (1),
PT2=PA×PB=12.8×5PT^2 = PA \times PB = 12.8 \times 5
PT2=64\Rightarrow PT^2 = 64
PT=8cm.\Rightarrow PT = 8\,\text{cm}.
=Length of tangent.= \text{Length of tangent.}
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